For what values k is the following continuous x=-dfrac{pi}{6} ?fleft( x right) = left{ begin{array}{l}dfrac{{sqrt 3 sin x + cos x}}{{x + dfrac{pi }{ 6}}},,,x ne - dfrac{pi }{6},,,,,,,,,,,,,,k,,,,,,,,,,,,,,,x = - dfrac{pi }{6 }end{array}
limit cosx -root 3 sin x x--pi/6 pi - 6x hope u understand due to lack of mathematical signs - Maths - Limits and Derivatives - 2843551 | Meritnation.com